Correlation tells you how strongly two variables move together, while linear regression gives you an equation to predict one from the other. Both appear constantly in FSc, A Level and university statistics, and both reduce to a handful of sums you can organise neatly. This guide explains the formulas and works through two complete examples.
What Correlation Measures
The Pearson correlation coefficient \( r \) measures the strength and direction of a linear relationship between two variables \( x \) and \( y \). It always lies between \(-1\) and \(1\):
- \( r = 1 \): perfect positive linear relationship.
- \( r = -1 \): perfect negative linear relationship.
- \( r = 0 \): no linear relationship (though a curved one might exist).
- Values like \( 0.8 \) or \( -0.8 \) are usually called strong; values near \( 0.3 \) are weak.
The Key Sums
Everything depends on three quantities, built from deviations about the means \( \bar{x} \) and \( \bar{y} \):
$$ S_{xx} = \sum (x - \bar{x})^2, \quad S_{yy} = \sum (y - \bar{y})^2, \quad S_{xy} = \sum (x - \bar{x})(y - \bar{y}) $$
Equivalent shortcut forms are \( S_{xx} = \sum x^2 - \frac{(\sum x)^2}{n} \) and \( S_{xy} = \sum xy - \frac{\sum x \sum y}{n} \).
The correlation coefficient is
$$ r = \frac{S_{xy}}{\sqrt{S_{xx} S_{yy}}} $$
The Least Squares Regression Line
The regression line of \( y \) on \( x \) is the straight line \( \hat{y} = a + bx \) that minimises the sum of squared vertical distances from the points to the line. Its coefficients are
$$ b = \frac{S_{xy}}{S_{xx}}, \qquad a = \bar{y} - b\bar{x} $$
Two useful facts:
- The line always passes through the point \( (\bar{x}, \bar{y}) \).
- The slope \( b \) and the correlation \( r \) always have the same sign.
The Coefficient of Determination
The value \( r^2 \) tells you the proportion of the variation in \( y \) that is explained by the linear relationship with \( x \). For example, \( r^2 = 0.6 \) means 60% of the variation is explained.
Worked Example 1: Positive Correlation
The data below show hours of revision \( x \) and test score \( y \) (out of 10) for five students.
| \( x \) | \( y \) | \( x - \bar{x} \) | \( y - \bar{y} \) |
|---|---|---|---|
| 1 | 2 | \(-2\) | \(-2\) |
| 2 | 4 | \(-1\) | 0 |
| 3 | 5 | 0 | 1 |
| 4 | 4 | 1 | 0 |
| 5 | 5 | 2 | 1 |
Step 1: Means.
$$ \bar{x} = \frac{1+2+3+4+5}{5} = 3, \qquad \bar{y} = \frac{2+4+5+4+5}{5} = \frac{20}{5} = 4 $$
Step 2: The sums.
$$ S_{xx} = 4 + 1 + 0 + 1 + 4 = 10 $$
$$ S_{yy} = 4 + 0 + 1 + 0 + 1 = 6 $$
$$ S_{xy} = (-2)(-2) + (-1)(0) + (0)(1) + (1)(0) + (2)(1) = 4 + 0 + 0 + 0 + 2 = 6 $$
Step 3: Correlation.
$$ r = \frac{6}{\sqrt{10 \times 6}} = \frac{6}{\sqrt{60}} \approx \frac{6}{7.746} \approx 0.775 $$
This is a fairly strong positive correlation.
Step 4: Regression line.
$$ b = \frac{6}{10} = 0.6, \qquad a = 4 - 0.6 \times 3 = 4 - 1.8 = 2.2 $$
$$ \hat{y} = 2.2 + 0.6x $$
Step 5: Interpret and predict. Each extra hour of revision is associated with a 0.6-mark increase. For \( x = 3.5 \) hours, \( \hat{y} = 2.2 + 0.6(3.5) = 2.2 + 2.1 = 4.3 \). Also \( r^2 = 36/60 = 0.6 \), so 60% of the variation in scores is explained by revision time.
Worked Example 2: Negative Correlation
Four students record daily hours of phone use \( x \) and a quiz score \( y \): \( (2, 10), (4, 9), (6, 6), (8, 3) \).
Step 1: Means.
$$ \bar{x} = \frac{2+4+6+8}{4} = 5, \qquad \bar{y} = \frac{10+9+6+3}{4} = \frac{28}{4} = 7 $$
Step 2: Deviations. \( x - \bar{x} \): \( -3, -1, 1, 3 \). \( y - \bar{y} \): \( 3, 2, -1, -4 \).
Step 3: The sums.
$$ S_{xx} = 9 + 1 + 1 + 9 = 20 $$
$$ S_{yy} = 9 + 4 + 1 + 16 = 30 $$
$$ S_{xy} = (-3)(3) + (-1)(2) + (1)(-1) + (3)(-4) = -9 - 2 - 1 - 12 = -24 $$
Step 4: Correlation.
$$ r = \frac{-24}{\sqrt{20 \times 30}} = \frac{-24}{\sqrt{600}} \approx \frac{-24}{24.495} \approx -0.980 $$
This is a very strong negative correlation.
Step 5: Regression line.
$$ b = \frac{-24}{20} = -1.2, \qquad a = 7 - (-1.2)(5) = 7 + 6 = 13 $$
$$ \hat{y} = 13 - 1.2x $$
Each extra hour of phone use is associated with a 1.2-point drop in quiz score. For \( x = 5 \), \( \hat{y} = 13 - 6 = 7 \), which matches \( \bar{y} \), as it must since the line passes through \( (\bar{x}, \bar{y}) \).
Common Mistakes
- Confusing correlation with causation. A strong \( r \) does not prove that \( x \) causes \( y \). A third factor may drive both.
- Extrapolating. Predicting far outside the range of your data (for example, 20 hours of revision above) is unreliable.
- Using \( r \) for curved data. A perfect parabola can have \( r = 0 \). Always sketch a scatter diagram first.
- Mixing up the regression lines. The line of \( y \) on \( x \) is for predicting \( y \). Predicting \( x \) from \( y \) requires a different line, \( b' = S_{xy}/S_{yy} \).
- Rounding too early. Keep full sums until the final step.
Key Takeaways
- \( r = S_{xy}/\sqrt{S_{xx}S_{yy}} \) measures the strength and direction of a linear relationship, from \(-1\) to \(1\).
- The least squares line is \( \hat{y} = a + bx \) with \( b = S_{xy}/S_{xx} \) and \( a = \bar{y} - b\bar{x} \).
- The regression line always passes through \( (\bar{x}, \bar{y}) \).
- \( r^2 \) gives the proportion of variation in \( y \) explained by \( x \).
- Correlation is not causation, and predictions are only trustworthy within the data range.
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